Resolving Power and Resolving Limit

The resolving power of an electron microscope is higher than that of an optical microscope because the wavelength of electron is _____________ as/than the wavelength of visible light.

What is the resolving power in optics

Define Resolving Power of Optical Instruments

What is the unit of resolving power?

. A grating has $16000$ per inch over a length of $5$ inches. What will be the smallest wavelength difference for a light of wavelength $6000 Å$.

Resolution power of electron microscope is

Resolving power of a microscope depends upon

Assume that the light of wavelength is $6000 \stackrel{\circ }{\mathrm{A}}$ coming from a star. What is the resolution limit of a telescope whose objective has a diameter of $100$ inch?

Resolving power of a microscope depends upon

Resolving power of a lens is the consequence of

The resolving power of the human eye is aprroximately-

If the red light is replaced by blue light illuminating the object in a microscope, the resolving power of the microscope

Out of the following, resolving power of reflecting telescope depends on: 
 

The diameter of the pupil of human eye is about $2 \mathrm{m}\mathrm{m}$. Human eye is most sensitive to the wavelength of $555 \mathrm{n}\mathrm{m}$. The limit of resolution of human eye is

An astronomical refracting telescope will have large angular magnification and high angular resolution, when it has an objective lens of

The ratio of resolving powers of an optical microscope for two wavelengths ${\lambda }_1=4000 \mathrm{Å}$ and ${\lambda }_2=6000\mathrm{ Å}$ is

The diameter of the lens of a telescope is 0.61m. Wave - length of light is $5000Å$ . The resolution power of the telescope is -

In order to find position of a microscopic object, a beam of light is used. To have maximum accuracy in the position of the object, the wavelength of light used

The diameter of an eye-lens is $2.5\times {10}^{-3}$ m and the refractive index of the eye fluid is 1.44. The resolve power of the eye for light of wavelength $5000 Å$ will be

Two spectral lines are just resolved if the central maximum of first line coincides with